Left - remove leading zeros and return number portion of st address, else return 0

[allredkj]

I'd like to extract the street number portion only for the address string and if none exists, I'd like it to return a '0'. An example of the data is below:

0005613Elliott Reeder Rd

0007601Glenview Dr

0007724Maplewood Ave

0007348Boulevard 26

0006120Watauga Rd # C (this row is null) I'd like to see the following after the formula is applied: 5613 7601 7724 7348 6120 0 I appreciate your assistance!!!

[eisayev]

=if(isnumber(mid(a8;4;4)+0);mid(a8;4;4)+0;0)

[CheshireCat]

If you are using Excel 2007 or later, then try:

=IFERROR(TEXT(LEFT(A2,7)*1,0),0)

[Zack Barresse]

If the number of leading zeros is not known, this will be more robust...

=LOOKUP(9.99E+307,--("0"&MID(A1,MIN(SEARCH({0,1,2,3,4,5,6,7,8,9},A1&"0123456789")),ROW(INDIRECT("1:"&LEN(A1))))))

This assumes you're looking at the value in A1.